If a particle is moving on a circular path with constant speed, then the angle between the direction of acceleration and its position vector w.r.t. centre of circle will be ............
$\pi$
$\frac{\pi}{2}$
Zero
$2 \pi$
A particle moves in a circle of radius $25\, cm$ at two revolutions per second. The acceleration of the particle in $m/{s^2}$ is
A stone of mass $0.3\,kg$ attached to a $1.5\,m$ long string is whirled around in a horizontal circle at a speed of $6\,m s ^{-1}$. The tension in the string is $............\,N$
The hour hand of a clock is $6\,cm$ long. The magnitude of the displacement of the tip of hour between $1:00\,PM$ to $5:00\,PM$ is
The centripetal acceleration is given by
The ratio of period of oscillation of the conical pendulum to that of the simple pendulum is : (Assume the strings are of the same length in the two cases and $\theta$ is the angle made by the string with the verticla in case of conical pendulum)