If a particle is moving on a circular path with constant speed, then the angle between the direction of acceleration and its position vector w.r.t. centre of circle will be ............ 

A particle is moving on a circular path of radius $r$ with uniform velocity $v$. The change in velocity when the particle moves from $P$ to $Q$ is $(\angle POQ = 40^\circ )$

The second's hand of a watch has $6\, cm$ length. The speed of its tip and magnitude of difference in velocities of its at any two perpendicular positions will be respectively

$Assertion$ : When a particle moves in a circle with a uniform speed, its velocity and acceleration both changes.

$Reason$ : The centripetal acceleration in circular motion is dependent on angular velocity of the body.

Figure below shows a body of mass $M$ moving with the uniform speed on a circular path of radius, $R$. What is the change in acceleration in going from ${P_1}$ to ${P_2}$

car moves on a circular road. It describes equal angles about the centre in equal intervals of time. Which of the following statement about the velocity of the car is true